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I am getting this error Exception ignored in: <_io.TextIOWrapper name='<stdout>' mode='w' encoding='cp1252'> OSError: [Errno 22] Invalid argument

Understanding and Resolving the OS Error Errno 22 Invalid Argument in Python If you are encountering the following error while running your Python script python

2 min read 15-09-2024 58
I am getting this error Exception ignored in: <_io.TextIOWrapper name='<stdout>' mode='w' encoding='cp1252'> OSError: [Errno 22] Invalid argument
I am getting this error Exception ignored in: <_io.TextIOWrapper name='<stdout>' mode='w' encoding='cp1252'> OSError: [Errno 22] Invalid argument